1 + 2 + … + 100
- Term f(i)
- Power i^p
- Lower limit (i starts at)
- 1
- Upper limit (i ends at)
- 100
- Power p
- 1
Result Sum: 5,050
Number of terms: 100
Mean term: 50.5
First term: 1
Last term: 100
- Σ from i = 1 to 100 of i^1, 100 terms.
- First term f(1) = 1, last term f(100) = 100.
- Closed form: n(n+1)/2 = 100 × 101 ÷ 2 = 5050.
The sum the young Gauss reportedly found by pairing 1 with 100, 2 with 99 and so on: 50 pairs of 101.