9 white LEDs from a 12 V supply
- Supply voltage
- 12
- LED forward voltage
- 3.2
- LED current
- 20
- Number of LEDs
- 9
Result Resistor per string (Ω): 120
LEDs in series per string: 3
Parallel strings: 3
Last string: Same as the others
Power in each resistor (mW): 48
Total supply current (mA): 60
Total power drawn (W): 0.72
Share of power reaching the LEDs: 80%
- LEDs per string = floor(12 V ÷ 3.2 V), keeping some voltage for the resistor = 3
- Strings = ceil(9 ÷ 3) = 3
- Resistor = (12 − 3 × 3.2) V ÷ 0.02 A = 120 Ω
- Resistor power = 2.4 V × 0.02 A = 48 mW
- Supply current = 3 × 20 mA = 60 mA
Three LEDs fit per string with 2.4 V to spare, so the nine LEDs form three strings, each with a 120 Ω resistor.