100 Ω + (200 Ω ∥ 200 Ω) at 12 V
- Circuit layout
- R1 + (R2 ∥ R3)
- R1
- 100
- R2
- 200
- R3
- 200
- Supply voltage
- 12
Result Equivalent resistance (Ω): 200
Inner combination (Ω): 100
Total current: 0.06 A
Total power: 0.72 W
- R2 ∥ R3 = (200 × 200) ÷ (200 + 200) = 100 Ω
- Total = R1 + (R2 ∥ R3) = 100 + 100 = 200 Ω
- Current I = V ÷ R = 12 ÷ 200 = 0.06 A
- Power P = V × I = 0.72 W
Two equal resistors in parallel halve to 100 Ω; the series 100 Ω brings the total to 200 Ω, which draws 60 mA from 12 V.