Oxygen in air at 1 atm
- Method
- Mole fraction
- Moles of this gas
- 20.95
- Total moles in the mixture
- 100
- Total pressure
- 1
- Pressure unit
- atm
Result Partial pressure (kPa): 21.23
In atmospheres (atm): 0.2095
In mmHg (torr): 159.22
In bar: 0.21228
Mole fraction: 0.2095
- Mole fraction x = 20.95 ÷ 100 = 0.2095
- Total pressure = 1 atm = 101.325 kPa
- p = x × P_total = 0.2095 × 101.325 = 21.2276 kPa
Oxygen is 20.95 of every 100 moles of dry air, so at one standard atmosphere it contributes 0.2095 atm, about 21.2 kPa.