5.844 g NaCl in 1000 mL
- Solve for
- Molarity
- Mass of solute
- 5.844
- Molar mass of solute
- 58.44
- Final solution volume
- 1000
- Volume unit
- mL
Result Result (mol/L, or grams to weigh): 0.1
Molarity (mol/L): 0.1
Millimolar (mmol/L): 100
Moles of solute (mol): 0.1
Mass of solute (g): 5.844
Mass concentration (g/L): 5.844
- Volume = 1000 mL = 1 L
- Moles n = 5.844 g ÷ 58.44 g/mol = 0.1 mol
- Molarity M = 0.1 mol ÷ 1 L = 0.1 mol/L
5.844 g of sodium chloride is one tenth of a mole, so made up to one litre it gives a 0.1 M solution, the classic teaching-lab stock.