pH 7 (pure water)
- pH
- 7
Result Hydrogen ion concentration [H+]: 1.00 × 10^-7 mol/L
[H+] as a decimal (mol/L): 1.00 × 10^-7 mol/L
pOH: 7
Hydroxide concentration [OH-]: 1.00 × 10^-7 mol/L
Solution is: Neutral
- [H+] = 10^(-pH) = 10^(-7) = 1.00 × 10^-7 mol/L
- pOH = 14 – pH = 14 – 7 = 7
- [OH-] = 10^(-pOH) = 1.00 × 10^-7 mol/L
At 25 °C neutral water holds 1.0 × 10^-7 mol of hydrogen ions per litre, the same as hydroxide.