36.03 g of water
- Find
- Moles from mass
- Molar mass
- 18.015
- Mass of sample
- 36.03
Result Result: 2 mol
Amount (moles): 2 mol
Amount (millimoles): 2000 mmol
Particles (Avogadro): 1.2044 × 10^24
- n = m ÷ M = 36.03 g ÷ 18.015 g/mol = 2 mol
- N = n × NA = 2 × 6.02214076 × 10^23 = 1.2044 × 10^24 particles
Water has a molar mass of 18.015 g/mol, so 36.03 g holds exactly 2 mol, about 1.2 × 10^24 molecules.