Point (3, 4) on x² + y² = 25
- Centre x (h)
- 0
- Centre y (k)
- 0
- Radius (r)
- 5
- Point x
- 3
- Point y
- 4
Result Tangent length from the point: 0
Point position: On the circle (one tangent)
Tangent line 1: y = -0.75x + 6.25
Tangent line 2: —
Point(s) of tangency: (3, 4)
Distance from centre to point: 5
Angle between tangents (degrees): 180
- Circle: (x − 0)² + (y − 0)² = 25
- Distance from centre to point d = √(3² + 4²) = 5
- d = r, so the point lies on the circle and there is one tangent, perpendicular to the radius.
- Tangent: (3)(x − 3) + (4)(y − 4) = 0 → y = -0.75x + 6.25
The radius to (3, 4) has slope 4/3, so the tangent has slope -3/4 and meets the y-axis at 25/4 = 6.25.