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Power Calculator (Electrical)

Known values
Power —
Power in kW
—
Voltage (V)
—
Current (A)
—
Resistance (Ω)
—

Electrical power is the rate energy is delivered: P = V × I. If you know current and resistance, use P = I² × R; with voltage and resistance, P = V² ÷ R. A kettle on 230 V drawing 10 A uses 2300 W, or 2.3 kW, and its element has a resistance of 23 Ω.

About this tool

Sizing a fuse, picking a resistor wattage or checking what an appliance pulls all come down to one number: power in watts. This calculator takes any pair of voltage, current and resistance, works out the power, and fills in the third quantity through Ohm's law so you can see the whole circuit at once. It also shows the result in kilowatts and writes out each line of the working. It treats the load as a pure resistance with DC or RMS AC values, so it does not account for power factor in motors, transformers or switch-mode supplies; for those, real power is lower than volts times amps.

How to use it

  1. Pick the pair you know

    Choose voltage and current, current and resistance, or voltage and resistance. Only the two matching fields are shown.

  2. Enter the values

    Type volts, amps or ohms. For mains AC use RMS values, such as 230 V or 120 V.

  3. Read power and the missing value

    Power appears in watts and kilowatts, along with the third quantity and the formula lines used.

Examples

230 V kettle drawing 10 A

Known values
Voltage and current
Voltage
230
Current
10

Result Power: 2,300
Power in kW: 2.3
Voltage (V): 230
Current (A): 10
Resistance (Ω): 23

  1. P = V × I = 230 V × 10 A = 2300 W
  2. R = V ÷ I = 230 ÷ 10 = 23 Ω

A typical European kettle element: 2.3 kW of heat from a 23 Ω element.

20 mA through a 220 Ω resistor

Known values
Current and resistance
Current
0.02
Resistance
220

Result Power: 0.088
Power in kW: 0.000088
Voltage (V): 4.4
Current (A): 0.02
Resistance (Ω): 220

  1. P = I² × R = 0.02² × 220 Ω = 0.088 W
  2. V = I × R = 0.02 × 220 = 4.4 V

0.088 W fits comfortably inside a 0.25 W resistor rating.

120 V across a 12 Ω heater

Known values
Voltage and resistance
Voltage
120
Resistance
12

Result Power: 1,200
Power in kW: 1.2
Voltage (V): 120
Current (A): 10
Resistance (Ω): 12

  1. P = V² ÷ R = 120² ÷ 12 Ω = 1200 W
  2. I = V ÷ R = 120 ÷ 12 = 10 A

V² ÷ R gives 1200 W, and the element draws 10 A.

How it is calculated

P = V × I = I² × R = V² ÷ R

P
power in watts (W)
V
voltage in volts (V)
I
current in amperes (A)
R
resistance in ohms (Ω)

Joule's law gives P = V × I. Substituting Ohm's law, V = I × R, yields the two other forms, so any two known quantities fix the power. The tool picks the form that matches your inputs, then uses Ohm's law again to report the quantity you did not enter. Kilowatts are watts divided by 1000.

When not to use it

  • Motors, compressors and LED drivers have a power factor below 1, so V × I overstates their real power.
  • Three-phase loads need the √3 factor and line voltage, which this form does not include.
  • Resistance of heating elements changes with temperature, so a cold ohmmeter reading gives too high a power.

Common mistakes

  • Entering milliamps as amps: 20 mA is 0.02 A.
  • Using peak AC voltage instead of RMS; 230 V mains peaks near 325 V.
  • Forgetting that power rises with the square of current in I²R, so doubling current quadruples the heat.

Frequently asked questions

Why are there three formulas for power?

They are one law written three ways. P = V × I is the definition, and replacing V with I × R or I with V ÷ R from Ohm's law gives I²R and V²/R. Use whichever matches the two values you have measured.

How many watts can a 13 A or 16 A socket supply?

At 230 V, 13 A allows about 2990 W and 16 A about 3680 W. At 120 V, a 15 A circuit gives 1800 W, though continuous loads are usually kept to 80 percent of that.

What resistor wattage do I need?

Work out I²R or V²/R for the resistor itself, then choose a part rated at roughly twice that value. A 220 Ω resistor carrying 20 mA dissipates 0.088 W, so a 0.25 W part leaves ample margin.

Does this work for AC circuits?

Yes, for resistive loads such as heaters, kettles and incandescent lamps, provided you enter RMS voltage and current. For inductive or electronic loads, multiply V × I by the power factor printed on the nameplate to get real watts.

How do I turn watts into energy used?

Multiply kilowatts by hours of use. A 2.3 kW kettle running for 6 minutes, 0.1 hour, uses 0.23 kWh. Your electricity bill is charged per kWh.

Why does a low resistance draw more power at the same voltage?

With fixed voltage, P = V² ÷ R, so halving resistance doubles power. That is why a short circuit, with resistance near zero, draws enough current to trip a breaker.

Cite this tool

Using this tool in an assignment, article or report? Copy a citation, or a link for your website.

APA

Tools Directory Editorial Team. (2026, October 12). Power Calculator (Electrical). Tools Directory. Retrieved October 26, 2026, from https://tools.milunir.com/electronics-physics/power-and-energy/power-calculator-electrical/

MLA

Tools Directory Editorial Team. “Power Calculator (Electrical).” Tools Directory, 12 Oct. 2026, https://tools.milunir.com/electronics-physics/power-and-energy/power-calculator-electrical/. Accessed 26 Oct. 2026.

Chicago

Tools Directory Editorial Team. “Power Calculator (Electrical).” Tools Directory. Last modified October 12, 2026. Accessed October 26, 2026. https://tools.milunir.com/electronics-physics/power-and-energy/power-calculator-electrical/.

Link<a href="https://tools.milunir.com/electronics-physics/power-and-energy/power-calculator-electrical/">Power Calculator (Electrical) – Tools Directory</a>